🧊 HVAC

Free Online Cold Room Load Calculator

Calculate cold room / cold store refrigeration load - transmission, product, infiltration and internal gains - in kW and TR. ASHRAE basis. Free online tool, no sign-up.

📐 Standard: ASHRAE Refrigeration
✅ Free to use
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🧊
Cold Room Load Calculator
Reference: ASHRAE Refrigeration
🧊 HVAC
Calculate cold room / cold store refrigeration load - transmission, product, infiltration and internal gains - in kW and TR. ASHRAE basis. Free online tool, no sign-up.
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ℹ️ About This Calculator

A cold room's refrigeration plant must remove heat from four sources: conduction through the insulated envelope, the product being cooled, air infiltration through doors, and internal gains from lights, fans and people. This calculator estimates the total load in kW and TR from the room size, temperatures and product data, following ASHRAE Refrigeration practice.

The four components rarely peak together, so a diversity and a safety factor (usually 10-20%) are applied to the total. Product load - cooling the goods and, for freezing, removing the latent heat of fusion - often dominates in a high-throughput store, while infiltration dominates where doors open frequently. Running the plant 16-18 hours a day, not 24, sets the design capacity.

📐 Cold Room Load Components

ASHRAE Refrigeration

Q_total = Q_trans + Q_product + Q_infil + Q_internal

Q_trans = U × A × ΔT  (envelope conduction)
Q_product = m × Cp × ΔT (+ latent for freezing)
Q_infil = air changes × volume × enthalpy diff
Q_internal = lights + fans + people + motors
Design capacity = Q_total × safety ÷ run hours/24

🧮 Worked Example

Example: A 5 × 4 × 3 m chill room at 2 °C in a 35 °C ambient, storing 2 tonnes of produce cooled 20 °C per day: transmission through 100 mm PUF is a few hundred watts, product load ≈ 2000 × 3.6 × 20 / (24×3600) ≈ 1.7 kW, plus infiltration and fan/light gains. Totalling and applying a 1.15 factor over an 18-hour run gives roughly 4-5 kW (about 1.3 TR).

📊 Cold Room Design Reference (ASHRAE)

Design temperatures and insulation drive the transmission load:

Store typeRoom tempTypical PUF insulation
Chiller (produce, dairy)0 to 4 °C80 – 100 mm
Cold store (meat)−2 to 2 °C100 mm
Freezer−18 to −25 °C125 – 150 mm
Blast freezer−30 to −40 °C150 – 200 mm

Load Components

Transmission grows with the temperature difference and thinner insulation; product load with throughput and (for freezers) the latent heat of freezing; infiltration with door openings and room volume. Add a 10-20% safety factor and size the plant on a 16-18 hour run so it can recover after defrost and door activity.

Indicative values - confirm against the ASHRAE Refrigeration Handbook and product cooling data.

Frequently Asked Questions

How do I calculate cold room refrigeration load? +
Add four heat sources - envelope transmission (U×A×ΔT), product load (mass × specific heat × temperature drop, plus latent heat for freezing), air infiltration, and internal gains from lights, fans and people - then apply a safety factor and divide by the daily run hours. This tool computes all four.
What is the biggest load in a cold room? +
It depends on use. In a high-throughput store the product load dominates; in a room with frequent door openings, infiltration dominates; in a well-used freezer with thin insulation, transmission can be significant. A balanced design considers all four.
How much insulation does a cold room need? +
Chillers at 0-4 °C typically use 80-100 mm of PUF; freezers at −18 to −25 °C use 125-150 mm; blast freezers up to 200 mm. Thicker insulation cuts the transmission load and running cost but raises the build cost.
How many hours a day should refrigeration run? +
Plant is usually sized to run 16-18 hours a day, not 24, leaving margin to recover after defrost cycles and heavy door activity. Dividing the daily load by these run hours gives the design capacity.
What is product load in refrigeration? +
It is the heat removed from the goods: the sensible heat to lower their temperature, plus, for freezing, the latent heat of fusion and any further cooling below freezing. High daily throughput makes product load the largest component.
How do I convert cold room load to TR? +
One ton of refrigeration (TR) equals about 3.517 kW. Divide the total load in kW by 3.517 to get TR. A 5 kW cold room load is about 1.4 TR.
What safety factor should I use? +
A 10-20% safety factor over the calculated load is typical, covering uncertainty in infiltration, ageing insulation and future load growth. It should not be so large that the plant short-cycles at low load.
Does door opening affect cold room load? +
Significantly. Each door opening lets warm, humid air in, adding infiltration load and frost. Air curtains, strip curtains, fast-acting doors and good discipline all reduce this - important for busy dispatch rooms.

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⚠️ Disclaimer: For preliminary engineering design only. Verify all results with a licensed engineer before use. Full disclaimer →